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Identify the magnetic nature of the anion of Na_(2)O_(2). |
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Answer» Solution :The ANION of `Na_(2)O_(2) " is "O_(2)^(2-)` (peroxide ion ). No. of electrons in `O_(2)^(2-) : 8 + 8 + 2 = 18 e^(-)` Electronic configuration: `( sigma_(1s))^(2) (sigma_(1s)^(**))^(2) ( sigma_(2)^(s))^(2)(sigma_(2)^(s^(**)))(sigma_(2)p_(Z))^(2)(pi_(2)p_(x))^(2)(pi_(2)p_(y))^(2)(pi_(2)^(**)p_(x))^(2) (pi_(2)^(**)p_(y))^(2)` Bond ORDER : `1/2 (N_(b) - N_(a)) = 1/2 (10 - 8) = 1` Magnetic Nature : Has no unpaired electrons. HENCE diamagnetic. |
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