Identify the oxidant and reductant in the following reactions: I_2(g)

1.	Identify the oxidant and reductant in the following reactions: I_2(g)+H_2S(g)to2IH(g) +S(s).
Answer» Solution :Writing the oxidation number of all the atoms above their symbols, we have `overset0(I_2)(g)+overset(+1)(H_2)overset(-2)(S)(g)tooverset(+1)(2H)overset(-1)I(g) +overset(0)S(s)` The oxidation number of `I_2` decreases from ZERO in `I_2` to -1 in HI, THEREFORE, `I_2` is reduced and HENCE it acts as an oxidant. THe O.N of S INCREASE from -2 in `H_2S` to zero in S, therefore , `H_2 S` is oxidised and hence it acts as the REDUCTANT.

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