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Identify the reagents shown in boid in the following equations as nucleophiles or electrophiles: (a) CH_(3)COOH + HO^(-) rarr CH_(3)COO^(-) + H_(2)O (b) CH_(3)COCH_(3) + bar(C )N rarr (CH_(3))_(2)C(CN)(OH) (c ) C_(6)H_(5) + CH_(3) overset(+)(C )O rarr C_(6)H_(5)COCH_(3) |
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Answer» SOLUTION :More suitable (c ) `C_(6)H_(5) + CH_(3) overset(+)(C )O rarr C_(6)H_(5)COCH_(3) + H^(+)` and (b) `CH_(3)COCH_(3) + H^(+) CN^(-) rarr (CH_(3))_(2) C(CN) (OH)` `because` Need to charge balance `{:("(a)" HO^(-)"is nucleophile reagent"),("(b)" ""^(-)CN "is NUCLEOPHILIC reagent"):}} {:("Because of (-)charge and octet so it is electron rich""):}` (c ) `CH_(3) overset(+)(C )O` is electrophilic because on CARBON sixtet, vacant orbital and electron deficient |
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