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Identify the substance undergoing oxidation, the substance undergoing reduction, the oxidising agent and the reducing agent in each of the following reactions. Cr_(2)O_(7)^(2-)+6Fe^(2+)+14H^(+)to2Cr^(3+)+6Fe^(3+)+7H_(2)O |
Answer» SOLUTION :For the given reaction, we have From the above, it is clear that the OXIDATION number of `Fe^(2+)` ion increases form +2 to +3. THEREFORE, `Fe^(2+)` ion gets oxidised and acts as a reducing agent. In `Cr_(2)O_(7)^(2-)` ion, the oxidation number of Cr decreases from +6 or +3. Hence, `Cr_(2)O_(7)^(2-)` ion gets reduced and acts as an oxidising agent. |
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