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IDOL18. 1€angle 15B35. Prove that the sum of any two sides of a triathan the third side.107cm, ZB=7.30

Answer»

Given ΔABC, extend BA to D such that AD = AC.Now in ΔDBC∠ADC = ∠ACD [Angles opposite to equal sides are equal]Hence ∠BCD > ∠ BDCThat is BD > BC [The side opposite to the larger (greater) angle is longer]Þ AB + AD > BC∴ AB + AC > BC [Since AD = AC)Thus sum of two sides of a triangle is always greater than third side.



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