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`IE "for" He^+ "is" 1.96 xx 10^-19 J "atom"^-1`. Calculate the energy of first stationary state of `Be^(+3)`.A. `6.84 xx 10^-19 J "atom"^-1`B. `6.84 xx 10^-23 J "atom"^-1`C. `7.84 xx 1019 J "atom"^-1`D. `7.84 xx 1023 J "atom"^-1` |
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Answer» Correct Answer - A For `He^+, E_1 = E_1 "fo"r H xx Z^2 = E_1 xx 4` For `Be^(3+), E_1 = E_1 "for" H xx Z^2 = E_1 xx 16` For `Be^(+3), E_1 = E_1 "for" He^+ xx (16)/(4)` =`1.96 xx 10^-19 xx 4` =`7.84 xx 10^-19 J//"atom"`. |
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