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,ienlllndtheValueoftanORLn (A + B) = 1 and tan (A-B) =|,0°<A+B<90°, A > B, therV3values of A and HB5 |
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Answer» Given,tan (A + B) = 1tan (A + B) = tan 45°A + B = 45........(1) tan (A - B) = 1/sqrt(3)tan (A - B) = tan 30°A - B = 30........(2) Add eq(1) and eq(2)2A = 75A = 75/2 = 37.5° Put value of A in eq(1), we get 37.5 + B = 45B = 45 - 37.5B = 7.5° |
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