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If 0.049 gof H_(2)SO_(4) are present in 10 litre of the solution, the pH of the solution will be |
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Answer» `:. ` Molar concentration `=(0.0049)/(98) M = 5 XX 10^(-5)M` `[H^(+)]=2[H_(2)SO_(4)]=2xx(5xx10^(-5))=10^(-4)M`. Hence, PH = 4 . |
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