1.

If 0.049 gof H_(2)SO_(4) are present in 10 litre of the solution, the pH of the solution will be

Answer»


Solution :Concentration of`H_(2)SO_(4)` solution = 0.049 G in 10 L = 0.0049 g `L^(-1)`
`:. ` Molar concentration `=(0.0049)/(98) M = 5 XX 10^(-5)M`
`[H^(+)]=2[H_(2)SO_(4)]=2xx(5xx10^(-5))=10^(-4)M`.
Hence, PH = 4 .


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