1.

If 0.08 Mole of HNO3 is required how many grams of HNO3 should be taken(atomic mass of some elements: c=12,O=16,H=1,N=14)​

Answer»

ANSWER: 5.04g

Explanation: MOLE=0.08

Molecular MASS=63

Mass in GRAM=?

Mole = mass/molecular mass

0.08 = mass/63

Mass = 63×0.08

Mass 5.04g



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