If 0.5 amp current is passed through acidified silver nitrate solution for 100 minutes the mass of silver deposited on cathode, is (eq. wt. of silver nitrate=108) :A. 2.3523 gB. 3.3575 gC. 5.3578 gD. 6.3575 g

If 0.5 amp current is passed through acidified silver nitrate solution

1.	If 0.5 amp current is passed through acidified silver nitrate solution for 100 minutes the mass of silver deposited on cathode, is (eq. wt. of silver nitrate=108) :A. 2.3523 gB. 3.3575 gC. 5.3578 gD. 6.3575 g
Answer» Correct Answer - B (b) Current (I) =0.5 amp. Time (t)=100 mm `=100xx60 sec.=6000 s`. Eq. mass of Ag (E ) =108 `W=(EIt)/(96500)=(108xx0.5xx6000)/(96500)=3.3575 g`.

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If 0.5 amp current is passed through acidified silver nitrate solution for 100 minutes the mass of silver deposited on cathode, is (eq. wt. of silver nitrate=108) :A. 2.3523 gB. 3.3575 gC. 5.3578 gD. 6.3575 g

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