If 0.50 mol of `BaCl_(2)` is mixed with 0.20 mol of `Na_(3)PO_(4)`, the maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed isA. `0.70`B. `0.50`C. `0.20`D. `0.10`

If 0.50 mol of `BaCl_(2)` is mixed with 0.20 mol of `Na_(3)PO_(4)`, th

1.	If 0.50 mol of `BaCl_(2)` is mixed with 0.20 mol of `Na_(3)PO_(4)`, the maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed isA. `0.70`B. `0.50`C. `0.20`D. `0.10`
Answer» Correct Answer - D `underset(0.5)(3 BaCl_(2))+ underset(0.2)(2 Na_(3) PO_(4)) rarr Ba_(3) (PO_(4))_(2)+6NaCl`, Limiting reagent in `Na_(3)PO_(4)` (0.2 mol), which gives 0.1 mol of `Ba_(3) (PO_(4))_(2)`.

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If 0.50 mol of `BaCl_(2)` is mixed with 0.20 mol of `Na_(3)PO_(4)`, the maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed isA. `0.70`B. `0.50`C. `0.20`D. `0.10`

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