If 0° < θ < 90°, is sin θ equal to cos (90° - θ), and for what reason? No, because angles measuring θ and 90° -θ are supplements. No, because angles measuring θ and 90° - θ are complements. Yes, because angles measuring θ and 90° - θ are supplements. Yes, because angles measuring θ and 90° - θ are complements.

If 0° < θ < 90°, is sin θ equal to cos (90° - θ), and for what r

1.	If 0° < θ < 90°, is sin θ equal to cos (90° - θ), and for what reason? No, because angles measuring θ and 90° -θ are supplements. No, because angles measuring θ and 90° - θ are complements. Yes, because angles measuring θ and 90° - θ are supplements. Yes, because angles measuring θ and 90° - θ are complements.
Answer» If 0° < θ < 90°, is sin θ equal to cos (90° - θ), and for what reason? No, because angles measuring θ and 90° -θ are supplements. No, because angles measuring θ and 90° - θ are complements. Yes, because angles measuring θ and 90° - θ are supplements. Yes, because angles measuring θ and 90° - θ are complements. Solution: