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If `1 1/2` moles of oxygen combine with Al to form `Al_(2)O_(3)` the weight of Al used in the reaction is (Al=27)A. (a)27 gB. (b)54 gC. (c )49.5 gD. (d)31 g |
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Answer» Correct Answer - B `2Al+3/2O_(2)rarr Al_(2)O_(3)` According to equation `3/2` mole of `O_(2)` combines with 2 moles Al. 2 mole `Al=54 g` |
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