1.

If 1.27 g Cu is obtained by reduction of one sample of Cu_(2)O then the amount of oxygen in sample is .......... g.

Answer»

16
8
1.6
0.16

Solution :MASS of Cu in SAMPLE of `Cu_(2)O=1.27g`
Mass of O in sample `=16 g`
If `Cu 127 g = O` is 16 g
`:.` If Cu `1.27g=(?)`
`:.(16xx1.27)/(127) = 0.16g` oxygen


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