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If 1.27 g Cu is obtained by reduction of one sample of Cu_(2)O then the amount of oxygen in sample is .......... g. |
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Answer» 16 Mass of O in sample `=16 g` If `Cu 127 g = O` is 16 g `:.` If Cu `1.27g=(?)` `:.(16xx1.27)/(127) = 0.16g` oxygen |
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