If "1 g cm s"^(-1)=x newton- second, then the number x is equal to:

1.	If "1 g cm s"^(-1)=x newton- second, then the number x is equal to:
Answer» `10^(5)` `10^(10)` `10^(15)` `10^(-5)` Solution :`x=(1gcms^(-1))/(1NS)=(1gcms^(-1))/(1kgxx1ms^(-2)xx1s)` `=(1gcms^(-1))/(10^(3)gxx10^(2)ms^(-2)xx1s)` `=(10gcms^(-1))/(10^(5)gcms^(-1))=10^(-5)`

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