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If 1 is a zero of the quadratic polynomial ax2 – 3(a – 1)x – 1 is 1, then find the value of a. |
Answer» Given: x = 1 is one zero of the polynomial ax2 – 3(a – 1) x – 1 Therefore, it will satisfy the above polynomial. Now, we have a(1)2 – (a – 1)1 – 1 = 0 ⇒ a – 3a + 3 – 1 = 0 ⇒ –2a = – 2 ⇒ a = 1 |
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