1.

If 1 kg of water contains 12 mg magnesium sulphate its degree of hardness is

Answer»

50 ppm
60 ppm
12 ppm
10 ppm

Solution :`13 MG MgSO_(4) rArr 12XX10^(-3) mg of MgSO_(4)`
`MgSO_(4)` HARDNESS `=(12xx10^(-3)g)/(10^(3)g)xx10^(6)g=12` ppm
`rArr 12g of MgSO_(4)` in `10^(6)g` of water
hardness in terms of `CaCO_(3)=12xx(100)/(12)=10` ppm


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