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If 1 kg of water contains 12 mg magnesium sulphate its degree of hardness is |
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Answer» 50 ppm `MgSO_(4)` HARDNESS `=(12xx10^(-3)g)/(10^(3)g)xx10^(6)g=12` ppm `rArr 12g of MgSO_(4)` in `10^(6)g` of water hardness in terms of `CaCO_(3)=12xx(100)/(12)=10` ppm |
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