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If 1 litre aq. Solution of `H_(2)SO_(4)` ( `10%` by weight) with density 1.1 gm/ml, find th `pH` of solution.A. `-log2.244`B. `-log1.96`C. `-log1.86`D. `-log3.87` |
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Answer» Correct Answer - A Let us take `100 gm` solution `implies 10 gm H_(2)SO_(4)` in `90 gm H_(2)O` `100/1.1 ml` solution `=10/98="mol" H_(2)SO_(4)` So, `M=(10xx1.1)/(98xx0.1)=110/98=1.122impliesN=2.244` `pH=-log2.244` |
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