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If 1 mole of acetic acid and 1 mole of ethyl alchol are mixed and reaction proceeds to equilibrium , the concentrations of acetic acid and water are found to be `1//3 and 2//3` mole respectively . If 1 mole of ethyl acetate and 3 moles of water are mixed , how much ester is present when equilibrium is reached ? |
Answer» Correct Answer - `0.465 " mole ". ` {:(,CH_(3)COOH ,+,C_(2)H_(5)OH,+,hArr,CH_(3)COOC_(2)H_(5),+,H_(2)O),("Intial amounts ",1 " mole ",,1 " mole ",,,,,),("Amounts at eqm.",1//3 " mole",,1//3 " mole",,,2//3 " mole",,2//3 " mole"),(" Molar concs.(mol " L^(-1),1//3 V,,1//3 V,,,2//3 V,,2//3 V):}` `K_(c) = ((2//3 V) (2//3 V))/((1//3 V) (1//3 V))=4` For the reverse reaction ` {:(,CH_(3)COOC_(2)H_(5),+,H_(2)O,hArr,CH_(3)COOH,+,C_(2)H_(5)OH),("Intial",1 " mole",,3 " moles",,,,),("At. eqm.",(1-x),,(3-x),,x,,x):}` ` :. (x^(2))/((1-x) (3-x))= 1/4 or 4 x^(2)= x^(2) + 3- 4 x or 3 x^(2) + 4 x - 3 = 0 ` `or x= (-4 pm sqrt(16+ 4 xx 3 xx 3))/(2 xx 3)=0*535 " mole"` `:. " Ester present at eqm."= 0*535 = 0*465 " mole " ` |
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