if (1-p) is root of quadratic equation x^2+px+(1-p)=0 then its roots a

1.	if (1-p) is root of quadratic equation x^2+px+(1-p)=0 then its roots are
Answer» As 1 – p is root of x² + px + 1 – p = 0 => (1 – p)² + p(1 – p) + (1 – p) = 0 (1 – p) [1 – p + p + 1] = 0 => p = 1 ∴ Given equation becomes x² + x = 0 So, Roots are x = 0, – 1

if (1-p) is root of quadratic equation x^2+px+(1-p)=0 then its roots are

Answer»

As 1 – p is root of x² + px + 1 – p = 0

=> (1 – p)² + p(1 – p) + (1 – p) = 0

(1 – p) [1 – p + p + 1] = 0

=> p = 1

∴ Given equation becomes x² + x = 0

So, Roots are x = 0, – 1

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if (1-p) is root of quadratic equation x^2+px+(1-p)=0 then its roots are

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