1.

If ∣∣∣∣∣1+sin2θcos2θ4sin4θsin2θ1+cos2θ4sin4θsin2θcos2θ1+4sin4θ∣∣∣∣∣=0 such that 0≤θ≤π2 then θ is

Answer»

If

1+sin2θcos2θ4sin4θsin2θ1+cos2θ4sin4θsin2θcos2θ1+4sin4θ

=0
such that 0θπ2 then θ is




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