If `(1+x-3x^2)^2145= a0 + a1x + a2x^2 + ......................`then `a0-a1+a2-a3+`...........ends with

If `(1+x-3x^2)^2145= a0 + a1x + a2x^2 + ......................`then `a

1.	If `(1+x-3x^2)^2145= a0 + a1x + a2x^2 + ......................`then `a0-a1+a2-a3+`...........ends with
Answer» Given=>`(1+x-3x^2)^2145=a_0+a_1x+a_2x^2......` substituting x=-1. =>`(-3)^2145=-(3)^2145=a_0-a_1+a_2......` cyclicity of 3=4. `3^2145=3^(4xx536+1)=>`so last digit will be 3.

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If `(1+x-3x^2)^2145= a0 + a1x + a2x^2 + ......................`then `a0-a1+a2-a3+`...........ends with

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