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If (1+x)n=n∑r=0arxr, then (1+a1a0)(1+a2a1)…(1+anan−1) is equal to |
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Answer» If (1+x)n=n∑r=0arxr, then (1+a1a0)(1+a2a1)…(1+anan−1) is equal to |
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