1.

If (1+x)n=n∑r=0nCrxr and n∑r=01nCr=a, then the value of ∑0≤i≤n ∑0≤j≤n(inCi+jnCj) is equal to

Answer»

If (1+x)n=nr=0nCrxr and nr=01nCr=a, then the value of 0in 0jn(inCi+jnCj) is equal to



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