1.

If (1+x+x2)20=a0+a1x+a2x2+⋯+a40x40, then the value of a0+3a1+5a2+⋯+81a40 is:

Answer»

If (1+x+x2)20=a0+a1x+a2x2++a40x40, then the value of a0+3a1+5a2++81a40 is:



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