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If `10^(21)` molecules are removed from 200 mg of `CO_(2)`, the number of moles of `CO_(2)` left will be ?A. `2.88 xx 10^(-3)`B. `1.66 xx 10^(-3)`C. `4.54 xx 10^(-3)`D. `1.66 xx 10^(-2)` |
Answer» Correct Answer - A No. of molecules in 200 mg of `CO_(2)` `= (6.022 xx 10^(23))/(44)xx0.2=2.73xx10^(21)` No. of molecules removed `= 10^(21)` No. of molecule left `= (27.73 xx 10^(21) - 1 xx 10^(21))` `= 1.73 xx 10^(21)` molecules No. of moles left`= (1.73xx10^(21))/(6.022xx10^(23))` `=2.87xx10^(-3)` |
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