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If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3). Flask at 300 K, calculate the number of moles of water is in vapour phase when equililbrium is established ? (V.P. of H_(2)O at 300 K is 3170 Pa ) |
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Answer» Solution :`P_(H_(2)O) = 3170 Pa = 3.17 xx 10^(-2)` atm From the ideal gas equation, PV = NRT NUMBER of moles, `n = (PV)/(RT)` ` = (3.17 xx 10^(-2) xx 1)/(0.0821 xx 300) = 1.27 xx 10^(-3)` mol |
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