If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3) flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established ? (Given : Vapour pressure of H_(2)O at 300 K is 3170 Pa , R=8.314 JK^(-1)mol^(-1))

If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3) flask at 30

1.	If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3) flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established ? (Given : Vapour pressure of H_(2)O at 300 K is 3170 Pa , R=8.314 JK^(-1)mol^(-1))
Answer» `4.46xx10^(-2)mol` `1.27xx10^(-3)mol` `5.5xx10^(-3)mol` `1.53xx10^(-2)mol` Solution :Vapour PRESSURE does not DEPEND upon the amount of WATER or size of the vessel. Hence, P=3170Pa. Also, `V=1 dm^(3)=10^(-3), T=300" K"` PV=nRT, `N=(PV)/(RT)=(3170xx10^(-3))/(8.314xx300)` `=1.27xx10^(-3)`