Saved Bookmarks
| 1. |
If 10–4 dm3 of water is introduced into a 1.0 dm3 flask to 300 K, how many moles of water are in the vapour phase when equilibrium is established?(Given : Vapour pressure of H2O at 300 K is 3170 Pa ; R = 8.314 J K–1 mol–1)(1) 5.56 x 10–3 mol (2) 1.53 x 10–2 mol (3) 4.46 x 10–2 mol (4) 1.27 x 10–3 mol |
|
Answer» (4) n = PV/RT = = 128 x 10-5 moles = (3770 x 10-5atm x 1L/0.0821 L atm k-1mol-1 x 300K) = 1.27 x 10-3 mol |
|