InterviewSolution
Saved Bookmarks
| 1. |
If `10^(6)` electrons pass from a point towards another point B in a conductor in one microsecond. Find the magnitude and direction of current. Give charge of an electron is `1.6 xx 10^(-19)` C. |
|
Answer» Here, `n=10^(6) , t=10^(-6)s`, `e =1.6 xx 10^(-19)C` Now, current `I= ("ne")/(t) = (10^(6) xx (1.6xx10^(-19)))/10^(-6)` `=1.6 xx 10^(-7)A` The direction of current is from B to A |
|