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If `10^(6)` electrons pass from a point towards another point B in a conductor in one microsecond. Find the magnitude and direction of current. Give charge of an electron is `1.6 xx 10^(-19)` C.

Answer» Here, `n=10^(6) , t=10^(-6)s`,
`e =1.6 xx 10^(-19)C`
Now, current `I= ("ne")/(t) = (10^(6) xx (1.6xx10^(-19)))/10^(-6)`
`=1.6 xx 10^(-7)A`
The direction of current is from B to A


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