If 10 ml of 6.0M HCl is neutralized by 150 mL of NaOH, what is the con

1.	If 10 ml of 6.0M HCl is neutralized by 150 mL of NaOH, what is the concentration of the base?(1) .4(2) 60(3) 90
Answer» Answer: 0.4 M Explanation: M1 × V1 = M2 × V2 6.0 × 10 = M2 × 150 M2 = 6 × 10/ 150 M2 = 0.4 M *HOPE* *THIS* *HELPS* *YOU*.....

If 10 ml of 6.0M HCl is neutralized by 150 mL of NaOH, what is the concentration of the base?(1) .4(2) 60(3) 90

Answer»

Answer:

0.4 M

Explanation:

M1 × V1 = M2 × V2

6.0 × 10 = M2 × 150

M2 = 6 × 10/ 150

M2 = 0.4 M

HOPE THIS HELPS YOU.....