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If `100 mL` of `H_(2) SO_(4)` and `100 mL` of `H_(2)O` are mixed, the mass percent of `H_(2) SO_(4)` in the resulting solution `(d_(H_(2)SO_(4)) = 0.09 g mL^(-1), d_(H_(2)O) = 1.0 mL^(-1))`A. 90B. 47.36C. 50D. 60 |
Answer» Correct Answer - B `X_(H_(2)SO_(4)) = (100 xx 0.9)/(100 xx 0.9 + 100 xx 1) = (90)/(190) = 0.4736` % mass of `H_(2)SO_(4) = 43.36%` |
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