

InterviewSolution
Saved Bookmarks
1. |
If `102!=2^(alpha)*3^(beta)*5^(gamma)*7^(delta)`…, thenA. `alpha=98`B. `beta=2gamma+1`C. `alpha=2beta`D. `2gamma=3delta` |
Answer» Correct Answer - A::B::C::D `becauseE_(2)(102!)=98,E_(3)(102!)=49`, `E_(5)(102!)=24 and E_(7)(102!)=16` `therefore alpha=98,beta=49,gamma=24 and delta=16` |
|