1.

If ∫11−cosx−sinxdx=ln∣∣∣tan[f(x)]−1tan[g(x)]∣∣∣+C, then the value of f(1)+g(1)−1=(where C is integration constant)

Answer» If 11cosxsinxdx=lntan[f(x)]1tan[g(x)]+C, then the value of f(1)+g(1)1=

(where C is integration constant)


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