1.

If∣∣∣∣111abca2b2c2∣∣∣∣=5, then ∣∣∣∣∣bc2−b2ca2c−ac2ab2−ba2b2−c2c2−a2a2−b2c−ba−cb−a∣∣∣∣∣ is equal to -

Answer» If
111abca2b2c2
=5
, then



bc2b2ca2cac2ab2ba2b2c2c2a2a2b2cbacba

is equal to -


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