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If ∫12x2+x−1dx=1kln∣∣∣2x−12x+2∣∣∣+C, then the value of k2+1 is(where C is integration constant)

Answer» If ∫12x2+x−1dx=1kln∣∣∣2x−12x+2∣∣∣+C, then the value of k2+1 is

(where C is integration constant)


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