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If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is(a) 10.2 eV(b) 0 eV(c) 3.4 eV(d) 6.8 eV |
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Answer» (c) 3.4 eV Explanation: En = \(\frac{13.6}{n^2}\) ⇒ E2 = \(\frac{13.6}{(2)^2}\) = 3.4 eV |
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