InterviewSolution
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InterviewSolution
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If `13.6eV` energy is required to separate a hydrogen atom into a proton and an electron, then the orbital radius of electron in a hydrogen atom isA. `5.3xx10^(-11)m`B. `4.3xx10^(-11)m`C. `6.3xx10^(-11)m`D. `7.3xx10^(-11)m` |
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Answer» Correct Answer - A Here, `E=-13.6eV=-13.6xx1.6xx10^(-19)=-2.2xx10^(-18)J` `E=(-e^2)/(8piepsilon_0r)` `therefore` As orbital radius, `r=(-e^2)/(8piepsilon_0E)=(9xx10^(9)xx(1.6xx10^(-19))^2)/(2xx(2.2xx10^(-18)))=5.3xx10^(-11)m`. |
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