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If 150 kJ of energy is needed for muscular work to walk a distance of one km , then how muchof glucoseone has to consumeto walk a distanceoffive km, provided only 30% energy is available for muscular work. Theenthalpy of combustion of glucoseis 3000kJ mol^(-1) |
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Answer» 75g 1 mole of glucose , `C_(6)H_(12)O_(6) ( 180g)` gives THEORETICALLY energy `= 3000kJ` Actual energy available`= ( 30)/( 100) XX 3000 = 900 kJ` Thus, for 900kJ of energy , glucose required `= 180 g` `:. `For 750 kJ of energy , glucose required`= ( 180)/( 900) xx750 g = 150 g` |
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