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If 16 gm of oxygen and x gm of hydrogen have the same volume at the same temperature and pressure, then find the value of x. |
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Answer» Solution :Mass of the oxygen gas `(m_(1))=16` GM ,Mass of th hydrogen gas `(m_(2))=x` From the PERFECT gas equation, PV = nRT `RARR PV=m/M""RT` Since from the given data, pressure volume and temperature are constant, `m/M` constant `therefore m_(1)/M_(1)=m_(2)/M_(2)" where "M_(1)" and "M_(2)` are the molecular weighs of oxygen and hydrogen `16/32=x/2, x=1gm` |
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