

InterviewSolution
Saved Bookmarks
1. |
If 18 g of glucose is present in 1000 g of solvent, the solution is said to beA. 1 molalB. 1.2 molalC. 0.5 molalD. 0.1 molal |
Answer» Correct Answer - D `(18)/(180xx1)=(1)/(10)=0.1` molal. |
|