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If ∫1cos2x(1−4tan2x)dx=K⋅ln∣∣∣1+2tanx1−2tanx∣∣∣+C, then 1K is(where C is integration constant)

Answer» If ∫1cos2x(1−4tan2x)dx=K⋅ln∣∣∣1+2tanx1−2tanx∣∣∣+C, then 1K is

(where C is integration constant)


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