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If `2^(7x-5)=(32)^(x-7)`, then find the value of `(1)/(2^x)`A. `2^17`B. `2^16`C. `2^15`D. None of these |
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Answer» Correct Answer - C Given `2^(7x-5)=(32)^(x-7)` `rArr 2^(7x-5)=2^(5x-35) (because 32=2^5)` `rArr 7x-5=5x=35` `rArr 2x=-30` `rArr x=-15` `therefore (1)/(2^x)=(1)/(2^-15)=2^15` Hence , the correct option is (c). |
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