1.

If ∣∣∣∣∣2−cos2xcos2x8sin2xcos2xsin2x2−sin2x8sin2xcos2xsin2xcos2x1+4sin4x∣∣∣∣∣=0where x∈(0,π), then the number of solutions is

Answer» If

2cos2xcos2x8sin2xcos2xsin2x2sin2x8sin2xcos2xsin2xcos2x1+4sin4x

=0
where x(0,π),

then the number of solutions is


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