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If `2 + isqrt3` is a root of `x^(3) - 6x^(2) + px + q = 0` (where `p` and `q` are real) then `p + q` is |
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Answer» Correct Answer - `1` `alpha = 2 + i sqrt(3)` `beta = 2 - i sqrt(3)` so `alpha + beta + gamma = +6` `gamma = 2` `alphabeta + betagamma + gammaalpha = p, alphabetagamma = -q` `7 + 2 (4) = p, q = -14`. `rArr p = 15` |
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