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If `2%` of the main current is to be passed through the galvanometer of resistance `G`, the resistance of shunt required isA. `G/49`B. `G/50`C. `49 G`D. `50G` |
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Answer» Correct Answer - A `I_G/I_S=S/G` `:. S=(I_G/I_S)G` `=(2/98)G=G/49` |
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