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If `(2+sinx)(dy)/(dx)+(y+1)cosx=0` and `y(0)=1`, then `y((pi)/(2))` is equal toA. `4/3`B. `1/3`C. `-2/3`D. `-1/3` |
Answer» Correct Answer - B We have `(2+sinx)(dy)/(dx) +(y+1)cosx=0` `rArr d/(dx)[(2sinx)(y+1)]=0` `rArr (2+sinx)(y+1)=c` Since `y(0)=1, c=4` So, `y+1=4/(2+sinx)` `therefore y(pi/2)=4/3-1=1/3` |
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