If 2 X + K Y is equal to 10 K intersect x-axis at(2,0) . Find k

1.	If 2 X + K Y is equal to 10 K intersect x-axis at(2,0) . Find k
Answer» Ye question mere exam me aaya tha The value of x and y is 2 and 02x+ky=10k Put the value of x and y 2(2)+k(0)=10k4+0=10kK=10/4K=2.5 2x+ky=10k ,(x=2,y=0),2(2)+k(0)=10k,4+0=10k,k=4/10,k=0.4 Given interesting poin (2,0).\'. X=2 and Y=0By putting the value of x and y in the equation (2x+ky=10k)We get, (2×2)+(k×0)=10k 4+0=10k => K=4/10=0.4 Hence the value of K is 0.4

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