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If `2 xx 10^(20)` electrons pass through a loop in one minute, What is the current in milliampere ? |
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Answer» Correct Answer - `533 mA` Here , `n = 2 xx 10^(20), t = 60 s` `I = (n e)/(t) = ((2 xx 10^(20))xx (1.6xx 10^(-19)))/(60)` `= 0.533 A = 533 mA` |
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