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If `20 cm^(3)` gas at `1 atm` is expanded to `50 cm^(3)` at constant `T`, then what is the final pressureA. `20xx(1)/(50)`B. `50xx(1)/(20)`C. `1xx(1)/(20)xx50`D. None of these |
Answer» Correct Answer - A At constant `T, P_(1)V_(1)=P_(2)V_(2)` `1xx20= P_(2)xx50, P_(2)=(20)/(50)xx1` |
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